image

Time Dilation

Time dilation is pretty much the basis for Einstein’s theory of special relativity. To explain what it is, it’s important to know what a frame of reference is. 

A common analogy used is to imagine someone is on a train bouncing a basketball. When the train is moving, whoever is bouncing the ball will simply see the ball moving up and down. However, to someone who is not  on the train, the ball will appear to move a bit like this:

This is an example of two different frames of reference, the one on the train and one off the train both observe different things. Now imagine that train is going really fast, like half of the speed of light, and replace the basketball with a device to measure time.

Since electromagnetic radiation (light) travels at the same speed in a vacuum, the ‘timer’ should measure light in some way. The timer, shown below, has an emitter that emits a photon or beam of light, and a receiver, that detects the light. For simplicity, I’m going to assume that L0 is very large compared to d0 so that the light travels directly up and down. The time taken for this process, which we call ∆t is equal to the distance the light travels, divided by the speed of light (c).

image

∆t= 2L0/c   (equation 1)

So while the train is not moving, both observers can agree on what ∆t  equals. When the train reaches a constant velocity, half the speed of light, the observer who didn’t get on the train will see train-person’s ‘timer’ do this:

image

Now the light has to travel much further to reach the receiver (rather than just straight up and down), and therefore the stationary observer sees the person on the having a slower time interval. Focusing on the frame on reference that the stationary observer is in, the time interval ∆t  is the same as equation 1, but from the stationary observer’s point of view, the time interval will be different

If you want to read the math part:

The distance, 2r, that the light travels will equal:

2r = 2√(L0 + (0.5c(∆t0)/2)2 )   (equation 2)

D = 0.5c(∆t0), because the train is moving at half the speed of light.

The new time measured by the stationary observer will be:

∆t’ = 2r/c   (equation 3)

Then after substituting equation 2 into equation 3 and a bit of algebra (which I won’t do because there’s already too much maths here) eventually you get this:

t’ = ∆t0 / [√(1 - [(0.5c)2/(c2)])]

Picture



158 notes
tagged as: relativity. science. time.

  1. positivityness-isnotaword reblogged this from 14-billion-years-later
  2. bioloxia reblogged this from 14-billion-years-later
  3. yggdrasil0 reblogged this from 14-billion-years-later
  4. stormbear reblogged this from oblivioncontinuum
  5. genialbrilliance reblogged this from revyourharley-archive
  6. revyourharley-archive reblogged this from sagansense
  7. trilingualinsanity reblogged this from 14-billion-years-later
  8. reesespenisbutter reblogged this from hesdeadjim
  9. the-beer-is-probably-people-too reblogged this from oblivioncontinuum
  10. startrekslut reblogged this from hesdeadjim
  11. hesdeadjim reblogged this from sagansense
  12. fractalnarrative reblogged this from sagansense
  13. zecaptaintuna reblogged this from subatomiconsciousness
  14. un-planned-plans reblogged this from subatomiconsciousness
  15. devanohgangcook reblogged this from 14-billion-years-later
  16. saestream reblogged this from subatomiconsciousness
  17. beautifulpropaganda reblogged this from subatomiconsciousness
  18. leonerdnimoy reblogged this from sagansense